Kansas City Chiefs coach Andy Reid announced on Wednesday that wide receiver Dwayne Bowe will start on Sunday night in Denver against the Broncos despite Bowe's arrest for marijuana possession in Riverside, Missouri on November 10.

Riverside police stopped the 29-year-old Bowe last Sunday night for going 13 miles over the speed limit. Officers searched Bowe's Audi A8 after detecting a strong odor of pot and found three containers of cannabis; 6.5 grams of popular strain "Bubba Kush,” 3.8 grams of "Fire 0.6" and the third vial (which was labeled as “medicinal cannabis from California”) held 4.2 grams of "Apollo 11.” All told, cops found 14.5 grams of pot – roughly half an ounce.

Bowe allegedly told the officers that his brother may have mistakenly put the medical marijuana in his travel bag, but then he also allegedly admitted to the cops he had smoked pot earlier that evening while at an airport. Additionally, he allegedly asked one of the officers if  “Sonic was still open at this time,” apparently hoping for a late night snack.

Bowe's presence is considered crucial as the surprisingly undefeated 9-0 Chiefs need all hands on deck to face Peyton Manning and the powerful 8-1 Broncos for first place in the NFL's AFC West. Besides being an underrated blocker, Bowe is second on the Chiefs with 33 catches and third with 369 receiving yards. He has been practicing with the team as usual this week. 

Reid justified his decision by noting: "Dwayne's been a team player since I've been here ... He doesn't want to bring any problems."

Bowe issued a public apology on Wednesday, although his attorney released a statement that same day declaring Bowe's total innocence in the case. Bowe is scheduled to appear in court on December 18, and if convicted of the drug charge, would be subject to the NFL's substance abuse policy, likely facing a suspension at some point.